What is the volume of 0.500 moles of nitrogen gas at 2.45 atmospheres pressure and a temperature of 303 k? (r=0.0821 l · atm/mol · k)

5.08 L

Explanation:

Given data

We can find the volume of gaseous nitrogen using the ideal gas equation.

P × V = n × R × T

V = n × R × T/ P

V = 0.500 mol × (0.0821 L.atm/mol.K) × 303 K/ 2.45 atm

V = 5.08 L

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.