When 200 grams of water cools from 50.°c to 25°c, the total amount of heat energy released by the water is?

We will use the formula q = mCΔT. where q = heat energy released. m= mass. C= specific heat of water. ΔT= change in temperature. Specific heat of water has not been given so we will just use the standard value of that which is 4.186J/g °C. q = mCΔT. q = 200 × 4.186 × (50 -25) q = 200 × 4.186 × 25 q = 5000 × 4.186 q = 20, 930 The total amount of energy released is 20, 930 J

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Olá. porque a reação na temperatura é muito rapida a do copo : )