Predict the precipitate produced by mixing an al(no3)3 solution with a naoh solution. write the net ionic equation for the reaction. (include the states of matter.)

The reaction of Al(NO3)3 solution with NaOH can be illustrated in the following equation:
Al(NO3)3 (aq) + 3 NaOH (aq) > Al(OH)3 (s) + 3 NaNO3 (aq)

The products of the equation are:
NaNO3 which is soluble in water 
Al(OH)3 which is insoluble in water
Therefore:
The precipitate is Al(OH)3

Now, for the ionic equation:
The total ionic equation is:
Al^+3(aq) + 3 NO3^-(aq) + 3Na^+(aq) + 3OH^-(aq) ---> Al(OH)3(s) + 3Na^+(aq) + 3 NO3^-(aq)
Therefore, the net ionic equation is:
Al+3 (aq) + 3 OH- (aq) > Al(OH)3 (s)

Ido not understand. 

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