How many moles of co2 form when 58.0 g of butane, c4h10, burn in oxygen? 2c4h10+> 8co2+10h2o

4 moles of are produced.

Explanation:

To calculate the number of moles, we use the formula:

For butane:

Given mass of butane = 58g

Molar mass of butane = 58 g/mol

Putting values in above equation, we get:

For the given chemical equation:

By Stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide

So, 1 mole of butane will produce = of carbon dioxide

Hence, 4 moles of are produced.

there all right good

explanation: