A0.1964-g sample of quinone (c6h4o2) is burned in a bomb calorimeter that has a heat capacity of 1.56 kj/c. the temperature of the calorimeter increases by 3.2c. calculate the energy of combustion of quinone per gram and per mole

Quinone mass in grams = 0.1964g 
Heat capacity = 1.56 KJ/C 
Temerature = 3.2C 
Heat energy that is lost while combustion, dH = heat capacity x temp  
dH = 1.56 KJ/c x 3.2c => dH = 4.992 KJ 
Since it is the energy lost, it is represented as dH = -4.992 KJ 
Calculating the heat energy per gram = 4.992/0.1964 = -25.4 KJ/m 
Molar weight of the compound is 108.1 g/mol 
Calculating the heat energy per mole = -25.4 KJ/g x 108.1 g/mol => -25.4 x
108.1 KJ/mol 
Heat energy per mole = -2747.63 KJ/mol

You know how the first one if filled up like the objects do the same but with the other categories

They can measure  the amount of energy gained or lost