What is the freezing point of an aqueous 1.58 molal nacl solution?

Tf is the freezing point of the solution(the solvent plus solute). T*f is the freezing point of the pure solvent(without solute) i is the van't Hoff factor.It is approximately the number of particles in solution that are made for each particle of the solute that is placed into solution.Therefore, for nonelectrolytes, i = 1. Kf is the freezing point depression constant.For water, Kf = 1.86 Degree C/m, or 1.86 Degree C.kg/mol. Tf is -1.58 Degree C

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