Asample of gas has an initial volume of 4.2 l at a pressure of 736 mmhg. if the volume of the gas is increased to 9.0 l , what will the pressure be? express your answer using two significant figures.

We will use Boyle's law. P = 1/V which simply means pressure is inversely proportion to volume at a constant temperature. We will assume temperature here does not change. Since we have two pressure/volume points, we use this version of Boyle's law.

P1 V1 = P2 V2

P  is pressure and V is volume

In our case:

P1 is 736, V1 is 4.2 while  V2 is 9.0 but P2 is unknown. This is what we need to find out.

736 * 4.2 = P2 * 9.0

P2 = 736 * 4.2 / 9.0

P2 = 3091.2 / 9.0

P2 = 343.5

Therefore the new pressure 343 mm/hg

Here we see that the increase in volume causes decrease in pressure in total agreement with Boyle's law.

i would say b

explanation:

but i think i would need more information than that