Lee dissolved 8 grams of a salt in a certain amount of water to obtain 608 grams of salt solution. what was the mass of the water used to make the solution?

600 g of the water was used to make the salt solution.

Explanation:

In a salt solution ,salt is present as a solute and water as a solvent.

Mass of salt present in the solution = 8 g

Mass of the salt solution = 608 g

Solution = Solvent + Solute

608 g = solvent + 8 g

Mass of water = 608 g - 8 g= 600 g

600 g of the water was used to make the salt solution.

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :