What is the molecular formula for the compound with a formula mass of 58.12 and an empirical formula of c2h5?

C₄H₁₀

Explanation:

The empirical formula is the reduced formula of the molecule. So, calling n the number of empirical formulas, the molecule formula will be:

n(C₂H₅)

The molar mass of C is 12 g/mol, and of H is 1 g/mol. So, the total mass will be:

nx(2x12 + 5x1) = 58.12

29n = 58.12

n = 2

Then, the molecular formula is:

2(C₂H₅) = C₄H₁₀

answer is: naturally occurring solid, inorganic compound or element is mineral.

minerals usually have crystalline form, that means than crystal constituents (atoms, molecules or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions.

for example magnetite is a mineral of iron oxide (fe₂o₃).

calcite is a carbonate mineral and the most stable polymorph of calcium carbonate (caco₃).

dolomite is an   carbonate mineral composed of calcium magnesium carbonate (camg(co₃)₂).

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.