The old car left on the side of the road showed signs of corrosion. we call this common chemical reaction rusting. the equation for this reaction can be written as 4fe + 3o2 → 2fe2o3. what are the reactants in the rusting process? a) iron oxide b) water and iron c) iron and oxygen eliminate d) water and iron oxide

Answer: Option (C)

Explanation:

The old car left on the side of the road showed signs of corrosion. we call this common chemical reaction rusting. The equation for this reaction can be written as

The reactants in the rusting process is iron and oxygen. rusting process is process of converting of metal to a form such as oxides and sulphides.

In  this chemical reaction 4 atoms of iron (fe) combines with 3 molecules of oxygen  to form rust, or 2 molecules of iron oxide  , which is a new product.

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

im pretty sure its b