Which is true about the effusion rates of helium and sulphur dioxide when the molar mass of helium is 4 grams/mole and the molar mass of sulphur dioxide is 64 grams?

Mv^2 is a conserved quantity so v goes as sqrt(1/m) heavier is slower 64/4 = 16 sqrt(16) = 4

The correct answer is c. orbital shape. "the angular momentum quantum number l describes the shape of an orbital. it corresponds to each orbital type, i.e. (0,1,2,−1)=(s,p,d,f,g,"