How many ml of a 0.300 m agno3 solution will it take to make 500 ml of a 0.100 m agno3 solution?

The answer is 166 mL. You use the formula V1*M1=V2*M2. For what you're given you rearrange the formula to V1=M2*V2/M1 so V1= (0.500 mL)(0.100 M AgNO3)/(0.300 M AgNO3) = 166 mL

We need 166, 7 mL of AgNO3 [0.300M] to prepare 500mL of AgNO3[ 0.100M]

Explanation:

When calculating the amount of volumen from an initial solution in order to prepare other one. we always use this formula for dilutions.

C1V1=C2V2

First we gather the information that will be replaced in our equation.

Inicial conditions that will be represented by  number 1

C1= 0.300M AgNO3

V1=  ?

Final conditions that will be represented by  number 2

C2= 0.100M AgNO3

V2=  500mL

Second, we replace the parameters giving in the equation and find out the value for V1.

V1= C2. V2 / C1

V1= 0.100M. 500mL /0.300M

V1= 166.7 mL

The answer is d- principle of faunal succession.

Answer is: the equilibrium  shifts toward the reactants, to the left side of chemical reaction.it is because lead(ii) nitrate dissociates in water: pb(no₃)₂ → pb²⁺(aq) + 2no₃⁻(aq).according to lechatelier's principle, the position of equilibrium moves to counteract thechange (more lead cations, common ion), the position of equilibrium will move so that the concentration ofproducts decrease and concentration of reactants of chemical reaction increase.read more on -