Of the molecules below, the bond in is the most polar. of the molecules below, the bond in is the most polar. hi hbr h2 hf hcl

The compound with the highest electronegativity is HF, Fluor being the most electronegative element that exists.

Explanation:

Hello!

Let's solve this!

To calculate the electronegativity of the compounds, the difference in electronegativity of each of the elements is calculated.

The data we need are:

Fluorine = 4.0

Chlorine = 3.16

Hydrogen = 2.1

Bromine = 2.96

Iodo = 2.66

The electronegativity of the compounds is:

HI: 2.66-2.1 = 0.56

HBr: 2.96-2.1 = 0.86

H2: 2.1-2.1 = 0

HF: 4-2.1 = 1.9

HCl: 3.16-2.1 = 1.06

After the calculations, we can conclude that the compound with the highest electronegativity is HF, Fluor being the most electronegative element that exists.

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72