How many bromine atoms are present in 35.2 g of ch2br2?

2.44*10²³ Br atoms.

Explanation:

To solve this problem we need to calculate the number of moles of CH₂Br₂ in 35.2 g.

35.2 g / 173.8 g·mol⁻¹ = 0.2025 mol CH₂Br₂

Now we use Avogadro's number to calculate the number of Br atoms in 0.2025 moles of CH₂Br₂, keeping in mind that there are 2 Br atoms for each CH₂Br₂ molecule:

0.2025 mol CH₂Br₂  * 2.44*10²³ Br atoms

answer is d because it is trust me