Asample of a hydrocarbon contains 20.75 g c and 4.25 g h. its molar mass is 58.04 g/mol. what is its empirical formula c2h5 ch2 ch c5h

Answer : The empirical formula is,

Solution : Given,

Mass of C = 20.75 g

Mass of H = 4.25 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Step 1 : convert given masses into moles.

Moles of C =

Moles of H =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =

For H =

The ratio of C : H = 1 : 2.5

In the whole number the ratio of C : H = 2 : 5

The mole ratio of the element is represented by subscripts in empirical formula.

Therefore, the empirical formula is,

the answer would be a