Label each reactant and product in this reaction as a bronsted acid or base. ch3oh +oh- < > ch3o- +h2o

In Bronsted acid base theory, 
acids are proton (H+) donors
bases are proton (H+) acceptors.

At the reaction, CH3OH (methly alcohol) donates one H+ to OH- ions (hydroxide). So that OH- becomes H2O with an extra H atom. (+) charge neutralizes (-) charge of ion. Notice that H2O is neutral.
Since CH3OH lose one positive H atom, it becomes CH3O-.

Donor is CH3OH, so it is the acid and its conjugate base is CH3O-
Acceptor is OH-, so it the base and its conjugate acid is H2O.