Calculate the volume in liters required to prepare a 5.00 m solution of nacl using 15.4 g of nacl

52.7 ml First, determine how many moles of NaCl you have Atomic weight sodium = 22.989769 Atomic weight chlorine = 35.453 Molar mass NaCl = 22.989769 + 35.453 = 58.442769 g/mol Moles NaCl = 15.4 g / 58.442769 g/mol = 0.263505653 mol Now molarity is defined as moles/liter, so let's set up an equation for the number of liters we can make. molarity = moles/liter Substitute the known values 5.00 = 0.263505653/liter And solve for liters 5.00 = 0.263505653/liter 5.00* liter = 0.263505653 liter = 0.263505653/5.00 liter = 0.052701131 So you can make 0.0527 liters of the solution. Or 52.7 ml

Hi. where is the graph?

The answer to that would be magnesium