You are provided with 6.05 g s o 2 to react with 2.23 g o 2 . indicate your theoretical yield.

7.56 g

Explanation:

Data: Molar masses

SO₂: 64.07 g/mol

O₂: 32.00 g/mol

SO₃: 80.07 g/mol

Let's consider the following balanced reaction.

SO₂ + 1/2 O₂ → SO₃

The theoretical mass ratio of SO₂ to O₂ is 64.07g to 1/2 × 32.00 g = 16.00 g, i.e. 4.004 g SO₂/ 1 g O₂.

The experimental mass ratio of SO₂ to O₂ is 6.05 g to 2.23 g, i.e. 2.713 g SO₂/ 1 g O₂.

Comparing both ratios, we can determine that SO₂ is the limiting reactant.

The mass ratio of SO₂ to SO₃ is 64.07 g to 80.07 g. The theoretical yield of SO₃ from 6.05 g of SO₂ is:

6.05 g SO₂ × (80.07 g SO₃/ 64.07 g SO₂) = 7.56 g SO₃

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