Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxide from these reactions.

2COâ‚‚ (g) + 6Hâ‚‚ (g) → CHâ‚OCHâ‚ (g) + 3Hâ‚‚O (â„“) Now make this reaction up from what you are given: 2 Ă— (COâ‚‚ (g) + 3Hâ‚‚ (g) → CHâ‚OH (l) + Hâ‚‚O (â„“).. â†H° = –131 kJ) ... (2CHâ‚OH (l) → CHâ‚OCHâ‚ (g) + Hâ‚‚O (â„“) .. â†H° = 8kJ) ––––––––––––––––––––––––––––––––––––––... add 2COâ‚‚ (g) + 6Hâ‚‚ (g) → CHâ‚OCHâ‚ (g) + 3Hâ‚‚O (â„“) . - exactly what you want! â†H° = 2(–131 kJ) + 8 kJ = –254 kJ

Change in speed or direction : )