What would be the formula of the compound iron (iii) phosphide? fe2p3 fe3p fep3 fep

Answer : The correct formula of the given compound will be,

Explanation :

Iron (III) phosphide is an ionic compound because iron element is a metal and phosphorous element is a non-metal. The bond formed between a metal and a non-metal is always ionic in nature.

The nomenclature of ionic compounds is given by:

1. Positive ion is written first.

2. The negative ion is written next and a suffix is added at the end of the negative ion. The suffix written is '-ide'.

3. In case of transition metals, the oxidation state are written in roman numerals in bracket in-front of positive ions.

The charge on iron is (+3) and the the charge on phosphide is (-3). The charges are balanced.

Hence, the formula of the compound iron (III) phosphide will be

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i