How many molecules of n2 are in a 300.0 ml container at 780 mmhg and 135â°c?

To solve for the number of molecules, we need to first find the number of moles. Assuming ideal gas, we use the formula:

n = PV / RT

where P is pressure = 780 mmHg, V is volume = 300 mL = 0.3 L, T is temperature = 135°C = 408.15 K, R is gas constant = 62.36367 L mmHg / mol K

n = (780 mmHg) (0.3 L) / (62.36367 L mmHg / mol K) (408.15 K)

n = 9.19 x 10^-3 mol

Using Avogadros number, we calculate the number of molecules.

molecules = 9.19 x 10^-3 mol * 6.022 x 10^23 molecules / mol

molecules = 5.54 x 10^21 molecules

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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