The molarity (m) of an aqueous solution containing 22.5 g of glucose (c6h12o6) in 35.5 ml of solution is

Explanation:

Molarity is the number of moles present in a liter of solution.

Mathematically,     Molarity =

And, no. of moles =

Molar mass of is 180.15 g/mol. Therefore, number of moles present will be as follows.

   No. of moles =

                         =

                          = 0.124 mol

Hence, calculate the molarity as follows.

                Molarity =

                       =      (as 1 L = 1000 mL)

                       = 3.51 M

Thus, we can conclude that molarity of the solution is 3.51 M.

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