How many grams of acetic anhydride are needed to react with 4.65 g of salicylic acid?

From the equation, one mole of acetic anhydride is needed to react with one mole of salicylic acid. From the stoichiometry of the equation, we get 4.65 g x 102.10 g acetic anhydride/1 mol divided by 138.13 g salicylic acid per mole. This gives us 3.44 g of salicylic acid.

Read the sentences below in 1962, i tried to enroll as the first black student at the university of mississippi. the governor of mississippi blocked my entrance which best describes the verbs used in the sentences? o they are past tense verbs, which are often used in narrative essays o they are past tense verbs, which are not often used in narrative essays. o they are future tense verbs, which are often used in narrative essays o they are future tense verbs, which are not often used in narrative essays.

C) electrons encircling a nucleus with neutrons and protons