What is the approximate difference in energy between the two chair conformations of trans-2-methyl-1-isopropylcyclohexa ne?

In the conformer I, both the substituents are in axial positions. Methyl group has two 1, 3 diaxial (HCH_3) interactions and isopropyl group has two 1, 3 diaxial (Hpr) interactions. Therefore, the energy of these interactions is given as (2x0.9) + (2x1.1) = 4.0kCal/mol.

In conformer II both the substituents are equatorial positions. So, axial interactions are absent and one gauche interaction between isopropyl and methyl groups exists therefore, the energy of this interaction is given as 1.1kCal/mol. The difference in the energy of two conformations is calculated as

E = (1.0 – 1.1) kCal/mol = 2.9 kCal/mol

The answer to the question is 2.9 kCal/mol

it is b that is the answer.

diaria maybe go see a doctor about that