Chemistry, 06.07.2019 07:50 nathang444
The formula for rust can be represented by fe2o3 how many moles of fe are present in 25.7 g
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Consider the reaction: 2al(s) + fe2o3(s) → al2o3(s) + 2fe(s) the δhf for fe2o3(s) = -824.3 kj/mole. the δhf for al2o3(s) = -1675.7 kj/mole. finish the equation. δhrxn = [(1)( kj/mole) + (2)( kj/mole)] - [(1)( kj/mole) + (2) ( kj/mole)]
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The formula for rust can be represented by fe2o3 how many moles of fe are present in 25.7 g...
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