Combustion analysis of naphthalene, a hydrocarbon used in mothballs, produced 8.80 g co2 and 1.44 g h2o . calculate the empirical formula for naphthalene.

In a complete combustion process, the products would be 1 mol of CO2 and 1 mol of H2O. In order to find out the amount of naphthalene reacted in the combustion process, you would need the relation of the mass of carbon with carbon dioxide (1 mol of CO2 = 1 mol C) and also the mass of hydrogen with water (1 mol H2O = 2 mol H). Convert the mass of CO2 and H2O given to moles of Carbon and Hydrogen respectively. You would get 0.1998 mol C and 0.1598 mol H. Then you would need to divide each with the smallest amount of moles present which is 0.1598. Thus you would get a ratio of 1.25 C: 1 H. Multiply this ratio with 4 in order to make it whole number. The empirical formula would be C5H4. 

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

2b2t

explanation:

2b2t