What is the molality of a solution that has 3 mol of glucose in 6 kg of water?

0.5 m

Explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

where,

n= moles of solute

Moles of glucose = 3 moles

= weight of solvent (water) in g  = 6 kg = 6000 g   (1kg=1000g)

Now put all the given values in the formula of molality, we get

Therefore, the molality of solution will be 0.5 mole/kg.

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b