If 28 ml of 5.8 m h2so4 was spilled, what is the minimum mass of nahco3 that must be added to the spill to neutralize the acid?

The mass of sodium hydrogen carbonate that must be added is 27.28 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

Molarity of sulfuric acid solution = 5.8 M

Volume of solution = 28 mL

Putting values in above equation, we get:

The chemical equation for the reaction of sulfuric acid and sodium hydrogen carbonate follows:

By Stoichiometry of the reaction:

1 mole of sulfuric acid reacts with 2 moles of sodium hydrogen carbonate.

So, 0.1624 moles of sulfuric acid will react with = of sodium hydrogen carbonate

To calculate the number of moles, we use the equation:

Molar mass of sodium hydrogen carbonate = 84 g/mol

Moles of sodium hydrogen carbonate = 0.3248 moles

Putting values in above equation, we get:

Hence, the mass of sodium hydrogen carbonate that must be added is 27.28 g

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