Calculate how much 95% ethyl alcohol will be required to dissolve 0.1 g of sulfanilamide at 78 c using volume calculate how much sulfanilamide will remain dissolved after mixture is cooled to 0

According to the source below, the solubility of sulfanilamide in 95% ethyl alcohol at 78°C is 210 mg/mL. Since 0.1 g = 100 mg, we can set up a proportion: 

(210 mg) / (1 mL) = (100 mg) / (x mL) Solving, x = 0.48 mL of 95% ethyl alcohol will be required.

I do not know previously the solubility of sulfanilamide in 95% ethyl alcohol. Let us accept the solubility you quoted here. 

100/210 = 0.47619047619.. ≈ 0.48 (ml) 

at 0C, the amount of sulfanilamide remains in the solution is: 14*(100/210) = 6.67 (mg), since you only have 0.48 ml solution. 

The volume of the solution will change a little by cooling from 78C to 0C. You may also consider this volume change if you have data.

Idon't see the pic?

No. an alpha particle is a pair of protons and a pair of neutrons, i.e. a helium