How many grams of sodium chloride are present in a 0.75 m solution with a volume of 500.0 milliliters?

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219.375 g of NaCl is present in a 0.75 M solution with a volume of 500.0 milliliter

Explanation: -

Volume of NaCl solution = 500 mL

= 500/1000 = 0.5 L

Strength of NaCl solution = 0.75 M

Number of moles of NaCl = Strength of NaCl x Volume of NaCl

= 0.75 M x 0.5 L

= 3.75 mol

Molar mass of NaCl = 23 x 1 + 35.5 x 1

= 58.5 g / mol

Mass of NaCl = Molar mass x number of moles

= 58.5 g / mol x 3.75 mol

= 219.375 g

the answer is: they rebelled against saddam hussein’s rule.

kurds opposed saddam rule and wanted independence. kurds in the north and shiites in the south revolt against hussein.

for example, the halabja attack in 1988 conducted against the kurdish people by the iraqi regime under saddam hussein, where between 4000 people are killed and around 9000 are injured.

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