Suppose that you have a supply of a 40% solution of alcohol and a 60% solution of alcohol. how many quarts of each should be mixed to produce 100 quarts that is 50% alcohol?

50 quarts of 60% solution and 50 quarts of 40% solution. You want a total of 100 quarts, so we'll use the following expressions x = amount of 60% solution (100 - x) = amount of 40% solution. The total amount of alcohol will be 0.6x + 0.4(100-x) We want the final result to be 100 quarts of 50% solution, so we express that as 0.5 * 100 Now we set them equal to each other, and solve for x 0.6x + 0.4(100-x) = 0.5 * 100 Distribute the .4 0.6x + 0.4*100 - 0.4x = 0.5 * 100 0.6x + 40 - 0.4x = 50 Subtract 40 from both sides and combine the x terms 0.2x = 10 Divide both sides by 0.2 x = 50 Now we know we need 50 quarts of the 60% solution. And we need (100 - 50) = 50 quarts of the 40% solution as well.

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.

Afraidsugar lol it’s the third one