How many kilojoules are needed to raise the temperature of 325 grams of water from 15.0 degrees c to 77.0 degrees c?

Given:
m = 325 g, the mass of water
ΔT = 77 - 15 = 62 °C, the change in temperature

Note that
c = 4.184 J/(g-°C), the specific heat of water.

Use the formula
Q = m*c*ΔT
where Q is the heat required for the change in temperature.

Q = (325 g)(4.184 J/g-°C)*(62 °C) = 8.43 x 10⁴ J
That is,
Q = 84.3 x 10³ J = 84.3 kJ

  84.3 kJ

Idon't see the pic?

Firstly, the water in the dams hold gravitational potential energy as they are above ground level. the gravitational potential energy is then transferred to kinetic energy as it falls, spinning the turbinethe turbine then spins the generator, which is a large magnet surrounded by metal coils. by doing this, the generator generates electricity. in this action, the energy transfer taken place is kinetic to electric energy