Chemistry, 30.06.2019 19:40 Yamari000

When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. how many grams of co can be formed from 35.0 grams of oxygen? 2c + o2 → 2co using 32.00 g/mole as the molecular mass of oxygen and 28.01 g/mole as the molecular mass of carbon monoxide, solve the above problem.

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Answer from: victoriavacodos

Considering the reaction stoichiometry, the mass of CO produced is 61.27 grams.

The balanced reaction is:

2 C + O₂ → 2 CO

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

C: 2 moles O₂: 1 mole CO: 2 moles

The molar mass of each compound is:

C: 12.01 $\frac{g}{mole}$ O₂: 32 $\frac{g}{mole}$ CO: 28.01 $\frac{g}{mole}$

Then, by reaction stoichiometry, the following amount of mass of each compound participate in the reaction:

C: 2 moles× 12.01 $\frac{g}{mole}$ = 24.02 grams O₂: 1 mole× 32 $\frac{g}{mole}$ = 32 grams CO: 2 moles× 28.01 $\frac{g}{mole}$ = 56.02 grams

Then you can apply the following rule of three: if by stoichiometry 32 grams of oxygen form 56.02 grams of CO, 35 grams of oxygen form how much mass of CO?

$mass of CO=\frac{35 grams of oxygenx56.02 grams of CO}{32 grams of oxygen}$

mass of CO= 61.27 grams

Finally, the mass of CO produced is 61.27 grams.

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Answer from: ellabarzyk128

The formula that denotes the incomplete combustion of carbon in the presence of a limited amount of oxygen is 2 C + O₂ → 2 CO

If the mass of oxygen that is used to combust carbon is 35 g
then the moles of oxygen = mass of oxygen ÷ molar mass of oxygen

= 35 g ÷ 32 g/mol

= 1.0938 mol

Now, the mole ratio of oxygen : carbon monoxide based on the balance equation is 1 : 2

⇒ If the mole of oxygen = 1.0938 mol
then the mole of carbon monoxide = 1.0938 × 2
= 2.1876 mol

Mass of CO is = mol of CO × molar mass of CO
= 2.1876 mol × 28 g/mol
= 61.25 g

∴ when a certain mass of carbon is combusted in 35g of oxygen then it produces approx. 61.25 g of Carbon Monoxide.

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

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When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. how many gram...