The double replacement reaction between potassium iodide and lead (II) nitrate is run in the lab with 65.00 g lead (II) nitrate producing 74.80 g lead (II) iodide. What is the percent yield for this reaction?

explanation:

detials on each model with digrams

i think its 100.

hope this !

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.