Consider the reaction; Mg + O2 → MgO Calculate the mass of magnesium oxide possible if 2.5 g Mg reacts with 5.0 g O2?

4.15g

Explanation:

Balance the reaction:

2Mg + O2 = 2MgO

Find limiting reactant from the two, by dividing miles with coefficient

2.5/24.3 = 0.103 moles/2 = 0.0515

5/16 = 0.31 moles/2 = 0.156

0.0515 is small than 0.156, so limiting reactant is Mg

Compare the ratio of Mg with MgO

Ratio is 2:2

So same moles = 0.103 moles

Mass = moles x molar mass of MgO

Mass = 0.103 x 40.3

= 4.15g

*please give brainlest*

he uptake of drugs from the intestine is often strongly influenced by diffusion. for example, consider a water-insoluble steroid for treating inflammation that is solubilized in aggregates of detergent molecules, called micelles. these micelles, aggregates of 80 soap molecules, have a molecular weight of 24,000, a diameter of 2.6 nm, and a charge of -27. the positively charge ions (counterions) in this system are na".