Balance the following chemical equation (if necessary) for the combustion reaction of glucose: C6H12O6(s) + O2(g) > CO2(g) + H2O(g)

The activation energy for this reaction is 75 kj·mol–1. the enzyme catalase (found in blood) lowers the activation energy to 8.0 kj·mol–1. at what temperature would the non-catalyzed reaction need to be run to have a rate equal to that of the enzyme-catalyzed reaction at 25°c?