HELP ME WITH THIS PLEASE! WILL MARK BRAINLIEST! Please be specific and label which one goes with each question!

3LiOH(aq)+VCI3(aq) --> 3LiCl(aq)+V(OH)3(s)

what is the complete ionic equation?

what is the net ionic equation?

what are the spectator ions?

Hello!

Complete ionic equations separate the equations into ion forms. Weak electrolytes and solids (precipitate) are exempt from this rule.

Net ionic equations are complete ionic equations but the ions that don't form as a precipitate are left out of the equation.

Anything cancelled out from the complete ionic equations are considered the spectator ions.

Looking at the equation, there are no weak electrolytes (you might have not covered this material yet), and the only precipitate in the solution is .

1. What is the complete ionic equation?

Let's ionize the equation. Make sure all the atoms are correspondent with their coefficients. Don't forget their charges.

Label every ion as (aq), and check the periodic table for their charges. Even without looking for V, we know that it is a 3+ charge since there are 3 chlorines attached to it.

2. What is the net ionic equation?

Get rid of all of the ions that don't do anything. Consider them lazy if they don't precipitate or form a solid. In this case, anything other than V and OH should be removed since they don't react. Think of it as cancelling out the ions that are still ions both sides.

3. What are the spectator ions?

Spectator ions are the cancelled out ions from the previous problem.

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation:

2b2t

explanation:

2b2t