Given the equations below, what is the heat of reaction for the process in which carbon monoxide is formed from its elements? C(s, graphite) + O2(g) → CO2(g), ∆H = –393.5 kJ

CO2(g) → CO(g) + ½O2(g), ∆H = 283.0 kJ

A) –676.5 kJ
B) 110.5 kJ
C) 676.5 kJ
D) –110.5 kJ

the answer is c

tell me if wrong

b.false that your answer

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally