I have a container of gas at a pressure of 2.4 atm and a temperature of 343 K with a moveable piston and a small opening that has an initial volume of 36 liters. If I raise the
pressure to 4.1 atm, decrease the temperature to 313 K, and measure the final volume
to be 51 liters, what is the final number of moles present inside the container if the
container held 3.7 moles to begin with? Give your answer in 2 decimals places.

d. temperate deciduous forest

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2