A hot iron ball is dropped into a 200. g sample of water initially at 50 0C. If 8.4 kJ of heat is transferred from the ball to the water, what is the final temperature of the water

The final temperature of the water after dropping the iron ball has been 60.
The heat transferred by the iron ball can be given by:
Heat (Q) = mcT
Q = heat transferred = 8.4 kJ
Q = 8400 J
m = mass = 200 g
c = specific heat = 4.2 J/g.
T = change in tempertaure = Initial temperature - final temperature
T = Final temperature - 50
8400 J = 200 g 4.2 J/g. (Final temperature - 50 )
Final temperature = 60.
The final temperature of the water after dropping the iron ball has been 60.

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