The Henry's law constant for O, is 1.3x10 ³ M/atm at 25 °C. What mass of oxygen would be dissolved in a 40-L aquarium at 25 °C, assuming an atmospheric pressure of 1.00 atm, and that
the partial pressure of O, is 0.21 atm?

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

b is the correct answer

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you did not give any options thus this is the best answer i can give to you with this little information you have given

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