Methanol (CH3OH) burns according to the equation 2CH3OH(l) + 3O2(g)  2CO2(g) + 4H2O(l), H°rxn = –1454 kJ/mol. How much heat, in kilojoules, is given off when 75.0 g of methanol is burned? A)727 kJD)1.70  103 kJ B)3.22  103 kJE)3.41  103 kJ C)1.45  103 kJ