How many grams of CaSO4 form when 50.0 mL of 0.20 M Ca(NO3)2 react with
excess potassium sulfate solution?
Ca(NO3)2 + K2SO4 → CaSO4 + 2KNO3
-
?] g CaSO4

Explanation:

.01 mol CaSO4 is the conversion factor between these values and now you just need to multiply it by the molar mass of .01 x 136.14=1.36g CaSO4

Apologies for having the wrong answer before this, it's been a long day.

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