A vapour-liquid mixture of water (1) and furfural C5H4O2 (2) is maintained at 1.013 bar and 109.5 oC. Under these conditions, it is found that x1 = 0.10 and y1 = 0.81. The temperature of the mixture is changed to 100.6 oC, and some (but not all) of the vapour condenses. The vapour phase may be assumed to behave as an ideal gas. The liquid-phase activity coefficients are independent of temperature but vary with concentration according to the van Laar equations. Determine: The activity coefficients for water and furfural at 1.013 bar and 109.5 oC and the van Laar constants Vapour pressure data T= 100.6degrees p^sat1= 1.0352 bar, p^sat2=0.1193bar
T=109.5degrees p^sat1=1.4088bar p^sat2=0.1690bar

c8h10 is your answerr

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole