The pa of hypochlorous acid is 7.530 . A 54.0 mL solution of 0.112 M sodium hypochlorite ( NaOCl ) is titrated with 0.282 M HCl . Calculate the pH of the solution after the addition of 8.39 mL of 0.282 M HCl.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally

50.23 i believe is correct but don't quote me on that.