How many grams of N2 are required to react with 4.2 moles of Mg in the following process? 3 Mg + N2 → Mg3N2? (Mg = 24.3 g/mol, N = 14.0 g/mol)

x = 0.45*28/3 = 4.2 g

Explanation:

showing work

N2 = 28 g/mole

3Mg + N2 → Mg3N2

3moles .. 28 g

0.45 moles .. x

x = 0.45*28/3 = 4.2 g (answer)

it is stable as it is in group 0 which have full outer shells of electrons