Consider the following reaction: Mg(s) + 2HCl(aq)
->
MgCl2 (aq) +H2(8)

If 0.475 g Mg reacts with 124.95 mL of 1.08 M HCl, how many mol of H2 gas will be produced?

Calculate the initial moles of Mg and HCl and find the limiting reactant?

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation:

if you mean hydrogen and oxygen then water is the product

i would say b

explanation:

but i think i would need more information than that