4. A student adds 50.0 mL of 0.25 M KCl solution to 25.0 mL 0.50 M AgNO3 solution. What is the mass of the precipitate that can be recovered if the percent yield of the reaction is 90%

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Following are the  advantages of the parametric equations: 1) they can be used to graph curves that are not functions, like the unit circle.2) the parameter can be used to represent the quantity that is  useful to  provide us with better information about the graph.3)  it is useful to convert between rectangular equations and parametric equations.with specific reference to chemistry,  parametric equations are employ for solving hydrogen and hydrogen-like ions, quantum mechanically. herein, cartesian coordinates are converted in spherical polar coordinates. the solution obtained, when plotted on spherical polar graph paper, provides visualization of atomic orbital such as s,p,d and f. 

D=m/v =57.9/3 = 19.3 g/cm^3