A 0.04365 g0.04365 g sample of gas occupies 10.0 mL at 291.5 K291.5 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C25.305% C and 74.695% Cl.74.695% Cl. What is the molecular formula of the compound

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally