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![\text{HNO}_3 (aq) \longrightarrow \text{H}^{+} + \text{NO}_3^{-} (aq)\\\\\text{Here ,} ~~ [ \text{H}^{+} ] = 0.056~ M\\\\\\\text{pH} = -\log[\text{H}^+}] = -\log(0.056) = 1.252](/tpl/images/2580/5751/01d5c.png)
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What is the ph of a 0. 056 m hno3 solution?....
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